In percentile scores,
general category
students, who get
79.63 percentile, will
qualify for
admissions.
Percentiles required
for other categories
are 79.607 for SCs,
79.55 for STs, 79.69
for OBC and 79.68 for
differently-abled
category.
Only those students who are among the top 20 percentilers in the
Intermediate Public Examination (IPE) while
considering all the
subjects would be
eligible to take
admission in the IITs in
the country this year.
This means that a
general category
student would have to
score 437 marks or
above out of 530 to
become eligible.
Earlier, the top 20
percentile criteria took
into account only the
marks scored in Maths,
Physics and Chemistry.
But the authorities have
decided to take into
account all the subjects
now. Following this,
sources in the Board of
Intermediate Education
detailed the cut-off
marks for students of
different categories.
While it would be 457
for general category
students, it would be
428, 387 and 396 for
OBC, SC and ST
candidates respectively.
In percentile scores,
general category
students, who get
79.63 percentile, will
qualify for admissions.
Percentiles required for
other categories are
79.607 for SCs, 79.55 for
STs, 79.69 for OBC and
79.68 for differently-
abled category. A total
of 1.5 lakh candidates
had written the JEE-
Advanced examination
on June 2.
Sources from the
secondary education
department said that
officials calculated the
top 20 percentile as
several requests were
coming from parents
and students asking for
the same. "The
document is, however,
not final as the actual
calculations are to be
done by IIT-Kanpur
which is in charge of
conducting the
examination. IIT-Kanpur
will announce the
results," an official said.
The rule under which
intermediate marks are
taken into account
while fixing the eligibility
criteria for students
was introduced this
year. Till last year, only
performance of
candidates in the
competitive
examination (JEE) was
considered.

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